Library Stlc.Lec2

Typing: preservation and progress


Require Import Metalib.Metatheory.
Require Import Stlc.Definitions.
Import StlcNotations.

Require Import Stlc.Lemmas.

Require Import Stlc.Lec1.

Typing contexts

We represent contexts as association lists (lists of pairs of keys and values) whose keys are atoms.
For STLC, contexts bind atoms to typs. We define an abbreviation ctx for the type of these contexts.
Lists are defined in Coq's standard library, with the constructors nil and cons. The list library includes the :: notation for cons as well as standard list operations such as append, map, and fold. The infix operation "++" is list append.
The Metatheory library extends this reasoning by instantiating the AssocList library to provide support for association lists whose keys are atoms. Everything in this library is polymorphic over the type of objects bound in the context. Look in AssocList for additional details about the functions and predicates that we mention below.
Context equality
When reasoning about contexts, we often need to talk about bindings in the "middle" of an context. Therefore, it is common for lemmas and definitions to use list append in their statements. Unfortunately, list append is associative, so two Coq expressions may denote the same context even though they are not equal.
The tactic simpl_env reassociates all concatenations of contexts to the right.

Lemma append_assoc_demo : (E0 E1 E2 E3:ctx),
  E0 ++ (E1 ++ E2) ++ E3 = E0 ++ E1 ++ E2 ++ E3.
Proof.
  intros.
  auto.   simpl_env.
  reflexivity.
Qed.

To make contexts easy to read, instead of building them from nil and cons, we prefer to build them from the following components:
  • nil: The empty list.
  • one: Lists consisting of exactly one item.
  • ++: List append.
The simpl_env tactic actually puts lists built from only nil, one and ++ into a "normal form". This process reassociates all appends to the right, removes extraneous nils and converts cons to singleton lists with an append.

Lemma simpl_env_demo : (x y:atom) (T1 T2:typ) (E F:ctx),
   ([(x, T1)] ++ nil) ++ (y,T2) :: (nil ++ E) ++ F =
   [(x,T1)] ++ [(y, T2)] ++ E ++ F.
Proof.
   intros.
   simpl_env.
   reflexivity.
Qed.

Context operations.
The ternary predicate binds holds when a given binding is present somewhere in an context.

Lemma binds_demo : (x:atom) (T:typ) (E F:ctx),
  binds x T (E ++ [(x, T)] ++ F).
Proof.
  auto.
Qed.

The function dom computes the domain of an context, returning a finite set of atoms. Note that we cannot use Coq's equality for finite sets, we must instead use a defined relation = for atom set equality.

Lemma dom_demo : (x y : atom) (T : typ),
  dom [(x, T)] [=] singleton x.
Proof.
  auto.
Qed.

The unary predicate uniq holds when each atom is bound at most once in an context.

Lemma uniq_demo : (x y : atom) (T : typ),
  x y uniq ([(x,T)] ++ [(y, T)]).
Proof.
  auto.
Qed.

Typing relation and cofinite quantification

The typing relation in the STLC definition states the typing rule for abstractions in a particular way.
typing_abs
     : forall (L : atoms) (G : ctx) (T1 : typ) (e : exp) (T2 : typ),
       (forall x : atom,
        x `notin` L -> typing ([(x, T1)] ++ G) (open e (var_f x)) T2) ->
       typing G (abs e) (typ_arrow T1 T2)
To show that abstractions are well-typed, we must show that the body of the abstraction is well-typed for any choice of variable, except those from some unspecified set `L`.
This type of rule differs from the quantification in the lc_abs rule (which does not restrict the variables at all) or the lc_abs_exists version (which only applies for one particular variable. We call this version "co-finite" quantification.
To see why this version is necessary, we will start with a more traditional version of the rules that only uses a single variable in the abs rule and then see what goes wrong. (We say that the typing_e judgement below uses "exists-fresh" quantification in the abs rule.)

Inductive typing_e : ctx exp typ Prop :=
  | typing_e_var : E (x : atom) T,
      uniq E
      binds x T E
      typing_e E (var_f x) T
  | typing_e_abs : x E e T1 T2,
      x `notin` dom E \u fv_exp e
      typing_e ([(x, T1)] ++ E) (e ^ x) T2
      typing_e E (abs e) (typ_arrow T1 T2)
  | typing_e_app : E e1 e2 T1 T2,
      typing_e E e1 (typ_arrow T1 T2)
      typing_e E e2 T1
      typing_e E (app e1 e2) T2.
Hint Constructors typing_e.

Weakening

Weakening states that if an expression is typeable in some context, then it is typeable in any well-formed extension of that context. This property is needed to prove the substitution lemma.
As stated below, this lemma is not directly proveable. The natural way to try proving this lemma proceeds by induction on the typing derivation for e.

Lemma typing_weakening_0 : E F e T,
  typing_e E e T
  uniq (F ++ E)
  typing_e (F ++ E) e T.
Proof.
  intros E F e T H J.
  induction H; auto.
  Case "typing_abs".
    apply (typing_e_abs x).
Abort.

We are stuck in the typing_abs case because the induction hypothesis IHtyping_e applies only when we weaken the context at its head. In this case, however, we need to weaken the context in the middle; compare the conclusion at the point where we're stuck to the hypothesis H, which comes from the given typing derivation.
We can obtain a more useful induction hypothesis by changing the statement to insert new bindings into the middle of the context, instead of at the head. However, the proof still gets stuck, as can be seen by examining each of the cases in the proof below.
Note: To view subgoal n in a proof, use the command "Show n". To work on subgoal n instead of the first one, use the command "Focus n".

Lemma typing_weakening_strengthened_0 : (E F G : ctx) e T,
  typing_e (G ++ E) e T
  uniq (G ++ F ++ E)
  typing_e (G ++ F ++ E) e T.
Proof.
  intros E F G e T H J.
  induction H.
  Case "typing_var".
  Focus 2.
  Case "typing_abs".
Abort.

The hypotheses in the typing_var case include an context G0 that that has no relation to what we need to prove. The missing fact we need is that G0 = (G ++ E).
The problem here arises from the fact that Coq's induction tactic lets us only prove something about all typing derivations. While it's clear to us that weakening applies to all typing derivations, it's not clear to Coq, because the context is written using concatenation. The induction tactic expects that all arguments to a judgement are variables. So we see E0 in the proof instead of (G ++ E).
The solution is to restate the lemma. For example, we can prove
  forall E F E' e T, typing E' e T ->
  forall G, E' = G ++ E -> uniq (G ++ F ++ E) -> typing (G ++ F ++ E) e T.
The equality gets around the problem with Coq's induction tactic. The placement of the ( G) quantifier gives us a sufficiently strong induction hypothesis in the typing_abs case.
However, we prefer not to state the lemma in the way shown above, since it is not as readable as the original statement. Instead, we use a tactic to introduce the equality within the proof itself. The tactic (remember t as t') replaces an object t with the identifier t' everywhere in the goal and introduces an equality t' = t into the context. It is often combined with generalize dependent, as illustrated below.

Lemma typing_weakening_strengthened_1 : (E F G : ctx) e T,
  typing_e (G ++ E) e T
  uniq (G ++ F ++ E)
  typing_e (G ++ F ++ E) e T.
Proof.
  intros E F G e T H.
  remember (G ++ E) as E'.
  generalize dependent G.
  induction H; intros G0 Eq Uniq; subst.
  - Case "typing_var". auto.
  - Case "typing_abs".
    eapply (typing_e_abs x).
Abort.

Print typing_abs.

At this point, we are very close. However, there is still one issue. We cannot show that x is fresh for the weakened context F.
This is the difficulty with the definition of typing_e. As in the local closure judgement, the induction hypotheses is not strong enough in the abs case.
However, this time, we take a slightly different solution, with the cofinite quantification of the typing_abs rule.
| typing_abs :
    forall (L : atoms) (G : ctx) (T1 : typ) (e : exp) (T2 : typ),
    (forall x, x `notin` L -> typing ([(x, T1)] ++ G) (e ^ x) T2) ->
    typing (abs e) (typ_arrow T1 T2) 
>>
The advantage of this definition is that it is easier to derive the "exists-fresh" version of the rule typing_e_abs as a lemma, than the version we used in lc_exp. (See below, we prove this lemma after we show substitution.) At the same time, this version of the rule is sufficiently expressive to complete the proof of weakening.

Exercise typing_weakening_strengthened

Complete the proof below, using the typing relation from Definitions.v.
HINTS:
  • The typing_var case follows from binds_weaken, the weakening lemma for the binds relation.
  • The typing_abs case follows from the induction hypothesis, but the apply tactic may be unable to unify things as you might expect.
    • - You'll need to specify the set to avoid with (L := dom (G0 ++ F ++ E) \u L)).
    • - In order to apply the induction hypothesis, use rewrite_env to reassociate the list operations.
    • - After applying the induction hypothesis, use simpl_env to use uniq_push.
    • - Here, use auto to solve facts about finite sets of atoms, since it will simplify the dom function behind the scenes. fsetdec does not work with the dom function.
  • The typing_app case follows directly from the induction hypotheses.

Lemma typing_weakening_strengthened : (E F G : ctx) e T,
  typing (G ++ E) e T
  uniq (G ++ F ++ E)
  typing (G ++ F ++ E) e T.
Proof.
  intros E F G e T H.
  remember (G ++ E) as E'.
  generalize dependent G.
  induction H; intros G0 Eq Uniq; subst.
Admitted.

Demo typing_weakening

We can now prove our original statement of weakening. The only interesting step is the use of the rewrite_env tactic.

Lemma typing_weakening : (E F : ctx) e T,
    typing E e T
    uniq (F ++ E)
    typing (F ++ E) e T.
Proof.
  intros E F e T H J.
  rewrite_env (nil ++ F ++ E).
  apply typing_weakening_strengthened; auto.
Qed.

Substitution

Having proved weakening, we can now prove the usual substitution lemma, which we state both in the form we need and in the strengthened form needed to make the proof go through.
  typing_subst_simple : forall E e u S T z,
    typing ([(z,S)] ++ E) e T ->
    typing E u S ->
    typing E ([z ~> u] e) T

  typing_subst : forall E F e u S T z,
    typing (F ++ [(z,S)] ++ E) e T ->
    typing E u S ->
    typing (F ++ E) ([z ~> u] e) T
The proof of the strengthened statement proceeds by induction on the given typing derivation for e. The most involved case is the one for variables; the others follow from the induction hypotheses.

Exercise typing_subst_var_case

Below, we state what needs to be proved in the typing_var case of the substitution lemma. Fill in the proof.
Proof sketch: The proof proceeds by a case analysis on (x == z), i.e., whether the two variables are the same or not.
  • If (x = z), then we need to show (typing (F ++ E) u T). This follows from the given typing derivation for u by weakening and the fact that T must equal S.
  • If (x z), then we need to show (typing (F ++ E) x T). This follows by the typing rule for variables.
HINTS: Lemmas binds_mid_eq, uniq_remove_mid, and binds_remove_mid are useful.

Lemma typing_subst_var_case : (E F : ctx) u S T (z x : atom),
  binds x T (F ++ [(z,S)] ++ E)
  uniq (F ++ [(z,S)] ++ E)
  typing E u S
  typing (F ++ E) ([z ~> u] (var_f x)) T.
Proof.
  intros E F u S T z x H J K.
  simpl.
Admitted.

Exercise typing_subst

Complete the proof of the substitution lemma. The proof proceeds by induction on the typing derivation for e. The initial steps should use remember as and generalize dependent in a manner similar to the proof of weakening.
HINTS:
  • Use the lemma proved above for the typing_var case.
  • The typing_abs case follows from the induction hypothesis.
    • - Use simpl to simplify the substitution.
    • - In order to use the induction hypothesis, use subst_var to push the substitution under the opening operation.
    • - Recall the lemma typing_to_lc_c and the rewrite_env and simpl_env tactics.
  • The typing_app case follows from the induction hypotheses. Use simpl to simplify the substitution.

Lemma typing_subst : (E F : ctx) e u S T (z : atom),
  typing (F ++ [(z,S)] ++ E) e T
  typing E u S
  typing (F ++ E) ([z ~> u] e) T.
Proof.
Admitted.

Exercise typing_subst_simpl

Complete the proof of the substitution lemma stated in the form we need it. The proof is similar to that of typing_weakening.
HINT: You'll need to use rewrite_env to prepend nil, and simpl_env to simplify nil away.

Lemma typing_subst_simple : (E : ctx) e u S T (z : atom),
  typing ([(z,S)] ++ E) e T
  typing E u S
  typing E ([z ~> u] e) T.
Proof.
Admitted.

Type soundness

Preservation

Recommended Exercise preservation

Complete the proof of preservation. In this proof, we proceed by induction on the given typing derivation. The induction hypothesis has already been appropriately generalized by the given proof fragment.
Proof sketch: By induction on the typing derivation for e.
  • typing_var case: Variables don't step.
  • typing_abs case: Abstractions don't step.
  • typing_app case: By case analysis on how e steps. The step_beta case is interesting, since it follows by the substitution lemma. The others follow directly from the induction hypotheses.


Lemma preservation : (E : ctx) e e' T,
  typing E e T
  step e e'
  typing E e' T.
Proof.
  intros E e e' T H.
  generalize dependent e'.
  induction H; intros e' J.
Admitted.

Progress

Exercise progress

Complete the proof of the progress lemma. The induction hypothesis has already been appropriately generalized by the given proof fragment.
Proof sketch: By induction on the typing derivation for e.
  • typing_var case: Can't happen; the empty context doesn't bind anything.
  • typing_abs case: Abstractions are values.
  • typing_app case: Applications reduce. The result follows from an exhaustive case analysis on whether the two components of the application step or are values and the fact that a value must be an abstraction.


Lemma progress : e T,
  typing nil e T
  is_value e e', step e e'.
Proof.
  intros e T H.

  assert (typing nil e T); auto.

  remember (@nil (atom × typ)) as E.

  induction H; subst.

Admitted.

Tactic support

When picking a fresh var or applying a rule that uses cofinite quantification, choosing a set of vars to be fresh for can be tedious. In practice, it is simpler to use a tactic to choose the set to be as large as possible.
The tactic gather_atoms is used to collect together all the atoms in the context. It relies on an auxiliary tactic, gather_atoms_with (from MetatheoryAtom), which maps a function that returns a finite set of atoms over all hypotheses with the appropriate type.

Ltac gather_atoms ::=
  let A := gather_atoms_with (fun x : atomsx) in
  let B := gather_atoms_with (fun x : atomsingleton x) in
  let C := gather_atoms_with (fun x : list (var × typ) ⇒ dom x) in
  let D := gather_atoms_with (fun x : expfv_exp x) in
  constr:(A `union` B `union` C `union` D).

A number of other, useful tactics are defined by the Metatheory library, and each depends on gather_atoms. By redefining gather_atoms, denoted by the ::= in its definition below, we automatically update these tactics so that they use the proper notion of "all atoms in the context."
For example, the tactic (pick fresh x) chooses an atom fresh for "everything" in the context. It is the same as (pick fresh x for L), except where L has been computed by gather_atoms.

Renaming

Substitution and weakening together give us a property we call renaming: (see typing_rename below that we can change the name of the variable used to open an expression in a typing derivation. In practice, this means that if a variable is not "fresh enough" during a proof, we can use this lemma to rename it to one with additional freshness constraints.
Renaming is used below to show the correspondence between the exists-fresh version of the rules with the cofinite version, and also to show that typechecking is decidable.
However, before we prove renaming, we need an auxiliary lemma about typing judgments which says that terms are well-typed only in unique contexts.

Lemma typing_uniq : E e T,
  typing E e T uniq E.
Proof.
  intros E e T H.
  induction H; auto.
  - Case "typing_abs".
    pick fresh x.
    assert (uniq ([(x, T1)] ++ G)); auto.
    solve_uniq.
Qed.

Demo: the proof of renaming.
Note that this proof does not proceed by induction: even if we add new typing rules to the language, as long as the weakening and substution properties hold we can use this proof.
Lemma typing_rename : (x y : atom) E e T1 T2,
  x `notin` fv_exp e
  y `notin` dom E
  typing ([(x, T1)] ++ E) (e ^ x) T2
  typing ([(y, T1)] ++ E) (e ^ y) T2.
Proof.
  intros x y E e T1 T2 Fr1 Fr2 H.
  destruct (x == y).
  - Case "x = y".
    subst; eauto.
  - Case "x <> y".
    assert (J : uniq ([(x, T1)] ++ E)).
      eapply typing_uniq; eauto.
    assert (J' : uniq E).
      inversion J; eauto.
    rewrite (@subst_exp_intro x); eauto.
    rewrite_env (nil ++ [(y, T1)] ++ E).
    apply typing_subst with (S := T1).
    simpl_env.
    + SCase "(open x s) is well-typed".
      apply typing_weakening_strengthened. eauto. auto.
    + SCase "y is well-typed".
      eapply typing_var; eauto.
Qed.

Exists-Fresh Definition

The use of cofinite quantification may make some people worry that we are not formalizing the "right" language. Below, we show that the "exists-fresh" version of the rules is the same as the cofinite version.

Lemma typing_abs_exists : E e T1 T2 (x : atom),
      x `notin` dom E \u fv_exp e
      typing ([(x,T1)] ++ E) (e ^ x) T2
      typing E (abs e) (typ_arrow T1 T2).
Proof.
  intros.
  apply typing_abs with (L := dom E \u fv_exp e).
  intros y Fr.
  apply typing_rename with (x:=x); auto.
Qed.

Exercise exists_cofinite


Lemma exists_cofinite : E e T,
    typing_e E e T typing E e T.
Proof.
Admitted.

Exercise cofinite_exists


Lemma cofinite_exists : G e T,
    typing G e T typing_e G e T.
Proof. Admitted.

Additional Exercises

Challenge Exercise fv_in_dom

We also want a property that states that the free variables of well-typed terms are contained within the domain of their typing contexts.
Lemma fv_in_dom : G e T,
    typing G e T fv_exp e [<=] dom G.
Proof.
Admitted.